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Question

Physics Question on Dual nature of matter

Light with an average flux of 20Ω/cm220\,\Omega/cm^2 falls on a non-reflecting surface at normal incidence having surface area 20cm220\,cm^2. The energy received by the surface during time span of 1minute1\,minute is :

A

10×103J10 \times 10^3J

B

12×103J12 \times 10^3J

C

24×103J24 \times 10^3J

D

48×103J48 \times 10^3J

Answer

24×103J24 \times 10^3J

Explanation

Solution

Energy received = Intensity ×\times Area ×\times Time
I=EAI=\frac{E}{A}
E=IAtE=IAt
=20104×20×104×60=\frac{20}{10^{-4}}\times 20\times 10^{-4}\times 60
=24×103J=24 \times 10^{3}\,J