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Question

Physics Question on Electromagnetic waves

Light wave travelling in air along xx-direction is given by Ey=540sinπ×104(xct)Vm1E_y=540 \sin \pi \times 10^4(x-c t) Vm ^{-1} Then, the peak value of magnetic field of wave will be (Given c=3×108ms1c =3 \times 10^8 ms ^{-1} )

A

18×107T18 \times 10^{-7} T

B

54×107T54 \times 10^{-7} T

C

54×108T54 \times 10^{-8} T

D

18×108T18 \times 10^{-8} T

Answer

18×107T18 \times 10^{-7} T

Explanation

Solution

Ey​=540sinπ×104(x−ct)Vm−1
E0​=540Vm−1
B0​=CE0​​=3×108540​=18×10−7T