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Question: Light travels in two media A and B with speeds \(1.8 \times 10 ^ { 8 } \mathrm {~ms} ^ { - 1 }\) and...

Light travels in two media A and B with speeds 1.8×108 ms11.8 \times 10 ^ { 8 } \mathrm {~ms} ^ { - 1 } and 2.4×108 ms12.4 \times 10 ^ { 8 } \mathrm {~ms} ^ { - 1 }respectively. Then the critical angle between them is:

A

sin1(23)\sin ^ { - 1 } \left( \frac { 2 } { 3 } \right)

B

tan1(34)\tan ^ { - 1 } \left( \frac { 3 } { 4 } \right)

C

tan1(23)\tan ^ { - 1 } \left( \frac { 2 } { 3 } \right)

D

sin1(34)\sin ^ { - 1 } \left( \frac { 3 } { 4 } \right)

Answer

sin1(34)\sin ^ { - 1 } \left( \frac { 3 } { 4 } \right)

Explanation

Solution

: Here, vA=1.8×108 ms1\mathrm { v } _ { \mathrm { A } } = 1.8 \times 10 ^ { 8 } \mathrm {~ms} ^ { - 1 }

Light travels slower in denser medium. Hence medium A is a denser medium and medium B is a rarer medium, Here, light travels from medium A to medium B. Let C be the critical angle between them.

Refractive index of medium B w.r.t. to medium A is

AμB= Velocity of light in medium A Velocity of light in medium B=vAvB{ } ^ { \mathrm { A } } \mu _ { \mathrm { B } } = \frac { \text { Velocity of light in medium } \mathrm { A } } { \text { Velocity of light in medium } \mathrm { B } } = \frac { \mathrm { v } _ { \mathrm { A } } } { \mathrm { v } _ { \mathrm { B } } }

or