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Question

Physics Question on Wave optics

Light of wavelength 5000×1010m5000 \times 10^{-10}m is incident normally on a slit The first minimum of the diffraction pattern is observed to lit at a distance of 5mm from the central maximum on a screen placed at a distance of 3m from the slit. Then the width of the slit is.

A

3 cm

B

0.3 cm

C

0.03 cm

D

0.01 cm

Answer

0.03 cm

Explanation

Solution

aa sin θ=nλ;aYD=nλ \theta = n \lambda ; a \frac{Y}{D} = n \lambda a=nλDY a = \frac{n \lambda D}{Y}