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Question: Light of two different frequencies whose photons have energies 1 eV and 2.5 Ev respectively, success...

Light of two different frequencies whose photons have energies 1 eV and 2.5 Ev respectively, successively illuminates a metal of work function 0.5 eV. The ratio of maximum kinetic energy of the emitted electron will be

A

1 : 5

B

1 : 4

C

1 : 2

D

1 : 1

Answer

1 : 4

Explanation

Solution

By using K0max⁡{K0}_{\max} ⇒

(K1max⁡(K2max⁡=1−0.52.5−0.5=0.52=14.\frac{({K1}_{\max}}{({K2}_{\max} = \frac{1 - 0.5}{2.5 - 0.5} = \frac{0.5}{2} = \frac{1}{4}.}