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Question

Physics Question on Kinetic Energy

Light of energy E falls normally on a metal of work function E3\frac{E}{3} . The kinetic energies (K) of the photo electrons are

A

k=2E3k=\frac{2E}{3}

B

k=E3k=\frac{E}{3}

C

O≤K≤2E3O≤K≤\frac{2E}{3}

D

O≤K≤E3O≤K≤\frac{E}{3}

Answer

O≤K≤2E3O≤K≤\frac{2E}{3}

Explanation

Solution

The correct answer is Option (C) : O≤K≤2E3O≤K≤\frac{2E}{3}