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Question

Mathematics Question on permutations and combinations

Letters in the word HULULULU are rearranged. The probability of all three L being together is

A

320\frac{3}{20}

B

25\frac{2}{5}

C

328\frac{3}{28}

D

523\frac{5}{23}

Answer

328\frac{3}{28}

Explanation

Solution

Given words, HULULULU
\therefore Total number of sample space =8!4!3!=\frac{8 !}{4 ! 3 !}
and total number of ways all three LL being together =6!41=\frac{6 !}{41}
Required probability =6!4!8!4!3!=\frac{\frac{6 !}{4!}}{\frac{8 !}{4 ! 3 !}}
=6!×3!8!=328=\frac{6! \times 3!}{8 !}=\frac{3}{28}

Discover More From Chapter:Permutations and Combinations