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Question

Mathematics Question on Complex Numbers and Quadratic Equations

Let zCz \in C with Im(z) = 10 and it satisfies 2zn2z+n=2i1\frac{2z-n}{2z+n} = 2i -1 for some natural number nn.Then :

A

n = 20 and Re(z) = - 10

B

n = 20 and Re(z) = 10

C

n = 40 and Re(z) = - 10

D

n = 40 and Re(z) = 10

Answer

n = 40 and Re(z) = - 10

Explanation

Solution

Put z=x+10iz = x + 10i
2(x+10i)n=(2i1).[2(x+10i)+n]\therefore 2(x + 10i) - n = (2i - 1) . [2(x+10i) + n]
compare real and imaginary coefficients
x=10,n=40x = - 10, n = 40