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Question: Let \(Y_{S}\)represent \(Y_{A}\)young’s modulus for steel and aluminium respectively. It is said tha...

Let YSY_{S}represent YAY_{A}young’s modulus for steel and aluminium respectively. It is said that steel is more elastic than aluminium. Therefore, it follows that

A

YS=YAY_{S} = Y_{A}

B

YS<YAY_{S} < Y_{A}

C

YS>YAY_{S} > Y_{A}

D

YSYA=0\frac{Y_{S}}{Y_{A}} = 0

Answer

YS>YAY_{S} > Y_{A}

Explanation

Solution

: Steel is more elastic than aluminium. It means YS>YAY_{S} > Y_{A}