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Question

Mathematics Question on types of differential equations

Let y=y(x)y=y(x) be the solution of the differential equation (3y25x2)ydx+2x(x2y2)dy=0\left(3 y^2-5 x^2\right) y d x+2 x\left(x^2-y^2\right) d y=0 such that y(1)=1y(1)=1 Then (y(2))312y(2)\left|(y(2))^3-12 y(2)\right| is equal to :

A

64

B

32232 \sqrt{2}

C

32

D

16216 \sqrt{2}

Answer

32232 \sqrt{2}

Explanation

Solution

The correct option is (B) : 32232 \sqrt{2}