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Question

Mathematics Question on Differential Calculus

Let y=(tanx)sinx for 0<x<π20\lt x\lt\frac{\pi}{2}. If dydx=(tanx)sinx((cosx)log(tanx)+g(x))\frac{dy}{dx}=(\tan x)^{\sin x}((\cos x)\log(\tan x)+g(x)), then g(x)=

A

sinx sec2x

B

secx cosecx

C

secx

D

cosecx

E

sinx tanx

Answer

secx

Explanation

Solution

The correct option is (C): secx