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Question

Statistics, Econometrics & Mathematical Economics Question on Variance

Let x1, x2 ….. xn be an independently, and identically distributed (iid) random sample drawn from a population that follows the Normal Distribution N(μ, σ2), where both the mean (μ) and variance (σ2) are unknown. Let xˉ\bar{x} be the sample mean. The maximum likelihood estimator (MLE) of the variance (σ^MLE2\hat{\sigma}^2_{MLE}) is/are then characterized by

A

σ^MLE2=1ni=1n(xixˉ)2{\hat{\sigma}}^2_{MLE}=\frac{1}{n}\sum^n_{i=1}(x_i-\bar{x})^2 which is a biased estimator of σ2

B

σ^MLE2=1ni=1n(xi2xˉ)2{\hat{\sigma}}^2_{MLE}=\frac{1}{n}\sum^n_{i=1}(x_i^2-\bar{x})^2 which is a consistent estimator of σ2

C

σ^MLE2=1n1i=1n(xixˉ)2{\hat{\sigma}}^2_{MLE}=\frac{1}{n-1}\sum^n_{i=1}(x_i-\bar{x})^2 which is an unbiased estimator of σ2

D

σ^MLE2=1n1i=1n1(xixˉ)2{\hat{\sigma}}^2_{MLE}=\frac{1}{n-1}\sum^{n-1}_{i=1}(x_i-\bar{x})^2 which is an unbiased and consistent estimator of σ2

Answer

σ^MLE2=1ni=1n(xixˉ)2{\hat{\sigma}}^2_{MLE}=\frac{1}{n}\sum^n_{i=1}(x_i-\bar{x})^2 which is a biased estimator of σ2

Explanation

Solution

The correct option is (A) : σ^MLE2=1ni=1n(xixˉ)2{\hat{\sigma}}^2_{MLE}=\frac{1}{n}\sum^n_{i=1}(x_i-\bar{x})^2 which is a biased estimator of σ2.