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Question

Statistics Question on Univariate Distributions

Let X1 and X2 be two independent and identically distributed discrete random variables having the probability mass function
f(x)={(12)x,x=1,2,3,... 0,otherwise. f(x) = \begin{cases} (\frac{1}{2})^x, & x=1,2,3,... \\\ 0, & \text{otherwise. } \end{cases}
Then P(min{X1 , X2} ≥ 5) equals

A

1256\frac{1}{256}

B

1512\frac{1}{512}

C

164\frac{1}{64}

D

9256\frac{9}{256}

Answer

1256\frac{1}{256}

Explanation

Solution

The correct option is (A) : 1256\frac{1}{256}.