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Question: Let ƒ(x) = (x – 3) (x – 4) (x – 5) (x – 6), then –...

Let ƒ(x) = (x – 3) (x – 4) (x – 5) (x – 6), then –

A

ƒ ¢ (x) = 0 has four roots

B

Three roots of ƒ ¢ (x) = 0 lie in (3, 4) Č (4, 5)Č (5, 6)

C

The equation ƒ ¢ (x) = 0 has only one root

D

Three roots of ƒ ¢ (x) = 0 lie in (2, 3) Č (3, 4)Č (4, 5)

Answer

Three roots of ƒ ¢ (x) = 0 lie in (3, 4) Č (4, 5)Č (5, 6)

Explanation

Solution

ƒ(x) = (x – 3) (x – 4) (x – 5) (x – 6)

Ž ƒ(3) = ƒ(4) = ƒ(5) = ƒ(6) = 0

\ by Rolle’s theorem, there exist

1 Ī (3, 4), a2 Ī (4, 5) and a3 Ī (5, 6) such that

Ģ (ai) = 0, i = 1, 2, 3.

Since ƒ¢(x) is a cubic polynomial therefore a1, a2, a3 are the only roots of ƒ ¢ (x) = 0.