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Question: Let ƒ(x) be a polynomial function of second degree. If f(1) = f(–1) and a, b, c are in A.P., then ƒ′...

Let ƒ(x) be a polynomial function of second degree. If f(1) = f(–1) and a, b, c are in A.P., then ƒ′(1), ƒ′(2), ƒ′(3) are in –

A

G.P.

B

H.P.

C

Arithmetic Geometric progression

D

A.P.

Answer

A.P.

Explanation

Solution

Let ƒ(x) = ax2 + bx + c

ƒ(1) = ƒ(–1) ⇒ a + b + c = a – b + c

⇒ 2b = 0

⇒ b = 0

∴ ƒ (x) = ax2 + c ∴ ƒ′(x) = 2ax

∴ ƒ′(1) = 2a2, ƒ′(2) = 2ab, ƒ′(3) = 2ac

Since a, b, c are in A.P.,

∴ ƒ′(1),ƒ′(2), ƒ′(3) are also in A.P.