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Question: Let X= {a,b,c} and consider the relation R= {(a,a), (b,b), (c,c)}. Then, R is...

Let X= {a,b,c} and consider the relation R= {(a,a), (b,b), (c,c)}. Then, R is

A

reflexive

B

transitive

C

symmetric

D

All of the above

Answer

All of the above

Explanation

Solution

Let the set be X={a,b,c}X = \{a, b, c\} and the relation be R={(a,a),(b,b),(c,c)}R = \{(a, a), (b, b), (c, c)\}.

We need to check if the relation R is reflexive, symmetric, and transitive.

  1. Reflexive: A relation R on a set X is reflexive if for every element xXx \in X, (x,x)R(x, x) \in R. In this case, X={a,b,c}X = \{a, b, c\}. We check if (a,a)R(a, a) \in R, (b,b)R(b, b) \in R, and (c,c)R(c, c) \in R. From the given relation R={(a,a),(b,b),(c,c)}R = \{(a, a), (b, b), (c, c)\}, we see that (a,a)R(a, a) \in R, (b,b)R(b, b) \in R, and (c,c)R(c, c) \in R. Thus, R is reflexive.

  2. Symmetric: A relation R on a set X is symmetric if for every pair (x,y)R(x, y) \in R, the pair (y,x)(y, x) is also in R. We check each pair in R:

    • For (a,a)R(a, a) \in R, we check if (a,a)R(a, a) \in R. Yes, it is.
    • For (b,b)R(b, b) \in R, we check if (b,b)R(b, b) \in R. Yes, it is.
    • For (c,c)R(c, c) \in R, we check if (c,c)R(c, c) \in R. Yes, it is. There are no pairs (x,y)(x, y) in R where xyx \neq y. The condition "if (x,y)R(x, y) \in R, then (y,x)R(y, x) \in R" is vacuously true for all pairs where xyx \neq y. For pairs where x=yx=y, the condition is "if (x,x)R(x, x) \in R, then (x,x)R(x, x) \in R", which is always true. Thus, R is symmetric.
  3. Transitive: A relation R on a set X is transitive if for every x,y,zXx, y, z \in X, whenever (x,y)R(x, y) \in R and (y,z)R(y, z) \in R, then (x,z)(x, z) must also be in R. We consider all possible combinations of pairs (x,y)(x, y) and (y,z)(y, z) that are both in R. The pairs in R are only of the form (element,element)(element, element). If (x,y)R(x, y) \in R, then xx must be equal to yy. If (y,z)R(y, z) \in R, then yy must be equal to zz. So, if (x,y)R(x, y) \in R and (y,z)R(y, z) \in R, it implies x=yx=y and y=zy=z, which means x=y=zx=y=z. The condition for transitivity becomes: If (x,x)R(x, x) \in R and (x,x)R(x, x) \in R, then (x,x)R(x, x) \in R. Since (x,x)(x, x) is in R for x{a,b,c}x \in \{a, b, c\}, this condition is satisfied. Thus, R is transitive.

Since the relation R is reflexive, symmetric, and transitive, it satisfies all three properties listed in options (a), (b), and (c). Therefore, option (d) is correct.