Question
Question: Let X= {a,b,c} and consider the relation R= {(a,a), (b,b), (c,c)}. Then, R is...
Let X= {a,b,c} and consider the relation R= {(a,a), (b,b), (c,c)}. Then, R is
reflexive
transitive
symmetric
All of the above
All of the above
Solution
Let the set be X={a,b,c} and the relation be R={(a,a),(b,b),(c,c)}.
We need to check if the relation R is reflexive, symmetric, and transitive.
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Reflexive: A relation R on a set X is reflexive if for every element x∈X, (x,x)∈R. In this case, X={a,b,c}. We check if (a,a)∈R, (b,b)∈R, and (c,c)∈R. From the given relation R={(a,a),(b,b),(c,c)}, we see that (a,a)∈R, (b,b)∈R, and (c,c)∈R. Thus, R is reflexive.
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Symmetric: A relation R on a set X is symmetric if for every pair (x,y)∈R, the pair (y,x) is also in R. We check each pair in R:
- For (a,a)∈R, we check if (a,a)∈R. Yes, it is.
- For (b,b)∈R, we check if (b,b)∈R. Yes, it is.
- For (c,c)∈R, we check if (c,c)∈R. Yes, it is. There are no pairs (x,y) in R where x=y. The condition "if (x,y)∈R, then (y,x)∈R" is vacuously true for all pairs where x=y. For pairs where x=y, the condition is "if (x,x)∈R, then (x,x)∈R", which is always true. Thus, R is symmetric.
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Transitive: A relation R on a set X is transitive if for every x,y,z∈X, whenever (x,y)∈R and (y,z)∈R, then (x,z) must also be in R. We consider all possible combinations of pairs (x,y) and (y,z) that are both in R. The pairs in R are only of the form (element,element). If (x,y)∈R, then x must be equal to y. If (y,z)∈R, then y must be equal to z. So, if (x,y)∈R and (y,z)∈R, it implies x=y and y=z, which means x=y=z. The condition for transitivity becomes: If (x,x)∈R and (x,x)∈R, then (x,x)∈R. Since (x,x) is in R for x∈{a,b,c}, this condition is satisfied. Thus, R is transitive.
Since the relation R is reflexive, symmetric, and transitive, it satisfies all three properties listed in options (a), (b), and (c). Therefore, option (d) is correct.