Question

Let $x = 2$ be a root of $y = 4x^2 - 14x + q = 0$. Then $y$ is equal to

• A. (x - 2) (4x - 6)
• B. (x - 2) (4x + 6)
• C. (x - 2) (-4x - 6)
• D. (x - 2) (-4x + 6)

Answer 1

Answer: (A)

(x - 2) (4x - 6)

Answer 2

We have
$y=4 x^{2}-14 x+q=0$
Since, $x=2$ is the root
$\therefore 4(2)^{2}-14(2)+q=0$
$\Rightarrow 16-28+q=0$
$\Rightarrow q=12$
$\therefore y=4 x^{2}-14 x+12$
$=4 x-8 x-6 x+12$
$=4 x(x-2)-6(x-2)$
$=(x-2)(4 x-6)$