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Question: Let w₁ and w₂ be two complex numbers satisfying |w₁| = 12 and |w₂ – 5 – 12i| = 25. Then, the minimum...

Let w₁ and w₂ be two complex numbers satisfying |w₁| = 12 and |w₂ – 5 – 12i| = 25. Then, the minimum value of |w₁ – w₂| is

A

0

B

5

C

13

D

12

Answer

0

Explanation

Solution

w1=12|w_1| = 12 implies w1w_1 is on a circle C1C_1 with center c1=0c_1 = 0 and radius r1=12r_1 = 12. w2(5+12i)=25|w_2 - (5 + 12i)| = 25 implies w2w_2 is on a circle C2C_2 with center c2=5+12ic_2 = 5 + 12i and radius r2=25r_2 = 25.

The distance between centers is d=c1c2=0(5+12i)=(5+12i)=52+122=25+144=169=13d = |c_1 - c_2| = |0 - (5 + 12i)| = |-(5 + 12i)| = \sqrt{5^2 + 12^2} = \sqrt{25 + 144} = \sqrt{169} = 13.

The absolute difference of the radii is r1r2=1225=13=13|r_1 - r_2| = |12 - 25| = |-13| = 13.

Since d=r1r2d = |r_1 - r_2|, the circles touch internally. The minimum distance between points on internally tangent circles is 0.