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Question

Mathematics Question on Vectors

Let a,b\vec{a}, \vec{b} and c\vec{c} be three non zero vectors such that bc=0\vec{b} \cdot \vec{c}=0 and a×(b×c)=bc2\vec{a} \times(\vec{b} \times \vec{c})=\frac{\vec{b}-\vec{c}}{2} If d\vec{d} be a vector such that bd=ab\vec{b} \cdot \vec{d}=\vec{a} \cdot \vec{b}, then (a×b)(c×d)(\vec{a} \times \vec{b}) \cdot(\vec{c} \times \vec{d}) is equal to

A

34\frac{3}{4}

B

12\frac{1}{2}

C

14-\frac{1}{4}

D

14\frac{1}{4}

Answer

14\frac{1}{4}

Explanation

Solution

(a⋅c)b−(a⋅b)c=2b−c​
a⋅c=21​,a⋅b=21​
∴b⋅d=21​
(a×b)⋅(c×d)=a⋅(b×(c×d))
=a⋅((b⋅d)c−(b⋅c)d)
=(a⋅c)(b⋅d)=41​