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Question

Mathematics Question on Vector Algebra

Let a=i^j^+2k^\vec{a}=\hat{i}-\hat{j}+2 \hat{k} and b\vec{b} be a vector such that a×b=2i^k^\vec{a} \times \vec{b}=2 \hat{i}-\hat{k} and ab=3\vec{a} \cdot \vec{b}=3 Then the projection of b\vec{b} on the vector ab\vec{a}-\vec{b} is :-

A

221\frac{2}{\sqrt{21}}

B

2372 \sqrt{\frac{3}{7}}

C

2373\frac{2}{3} \sqrt{\frac{7}{3}}

D

23\frac{2}{3}

Answer

221\frac{2}{\sqrt{21}}

Explanation

Solution

Projection of b on vector a−b is
=∣a−b∣b⋅(a−b)​
=a2+b2−2a⋅b​a⋅b−∣b∣2​=6+b2−6​3−b2​=b3−b2​
∣a×b∣2=5
a2b2−(a⋅b)2=5
6b2=14⇒b2=37​
∴b3−b2​=37​​3−37​​=2×21​