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Question

Mathematics Question on Vectors

Let a\vec a=i^\hat ij^\hat j+2k^\hat k and b\vec b be a vector such that
a\vec a×b\vec b=2i^\hat ik^\hat k and a\vec ab\vec b=3.
Then the projection of b\vec b on the vector a\vec ab\vec b is :

A

221\frac{2}{\sqrt{21}}

B

237\frac{2\sqrt3}{7}

C

2373\frac{2}{\frac{3\sqrt7}{3}}

D

23\frac{2}{3}

Answer

221\frac{2}{\sqrt{21}}

Explanation

Solution

a\vec a=i^\hat ij^\hat j+2k^\hat k
a\vec a×b\vec b=2i^\hat ik^\hat k
a\vec ab\vec b=3 |a\vec a×b\vec b|2+|a\vec ab\vec b|2
=|a\vec a|2⋅|b\vec b|2
⇒5+9=6|b\vec b|2
⇒|b|2=73\frac{7}{3}
|a\vec ab\vec b|=√|a\vec a|2+|b\vec b|2−2a\vec ab\vec b=73\frac{\sqrt7}{3}
projection of b\vec b on a\vec ab\vec b=b(ab)ab\frac{\vec b(\vec a-\vec b)}{|\vec a-\vec b|}
=221\frac{2}{\sqrt{21}}