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Question

Mathematics Question on Vector Algebra

Let aandb\vec{a} \,and\, \vec{b} be two unit vectors. If the vectors c=a^+2b^\vec{c} = \hat{a} + 2\hat{b} and d=5a^4b^\vec{d} = 5\hat{a} -4\hat{b} are perpendicular to each other,then the angle between a^\hat{a} and b^\hat{b} is :

A

π6\frac{\pi}{6}

B

π2\frac{\pi}{2}

C

π3\frac{\pi}{3}

D

π4\frac{\pi}{4}

Answer

π3\frac{\pi}{3}

Explanation

Solution

c=a^+2b^\vec{c} = \hat{a} + 2\hat{b} d=5a^4b^\vec{d} = 5\hat{a} -4\hat{b} c.d=0\vec{c}.\vec{d} = 0 (a^+2b^).(5a^4b^)=05+6a^.b^8=0\Rightarrow\quad\left(\hat{a}+2\hat{b}\right).\left(5\hat{a} -4\hat{b}\right) = 0\quad\quad\Rightarrow\quad5+6\hat{a}.\hat{b}-8 = 0 a^.b^=12θ=π3\Rightarrow\quad\hat{a}.\hat{b} = \frac{1}{2}\quad\quad\Rightarrow\quad \theta = \frac{\pi}{3}