Question

Let u(x) and v(x) are differentiable functions such that

$\frac{u(x)}{v(x)}$ = 7. If $\frac{u'(x)}{v'(x)}$ = p and $\left( \frac{u(x)}{v(x)} \right)^{'}$= q. Then $\frac{p + q}{p - q}$ (p ≠ 0) has the value equal to

• A. 1
• B. 0
• C. 7
• D. –7

Answer 1

Answer: (A)

1

Answer 2

$\frac{u(x)}{v(x)}$ = 7 so $\left( \frac{u(x)}{v(x)} \right)^{'}$ = 0 ⇒ q = 0; ratio = 1