Solveeit Logo

Question

Physics Question on physical world

Let us consider a system of units in which mass and angular momentum are dimensionless. If length has dimension of L, which of the following statement(s) is/are correct?

A

The dimension of linear momentum is L1L^{-1}

B

The dimension of energy is L2L^{-2}

C

The dimension of force is L3L^{-3}

D

The dimension of power is L5L^{-5}

Answer

The dimension of force is L3L^{-3}

Explanation

Solution

Angular momentum =MVR\ell=MVR
[]=ML2TM\Rightarrow \left[\ell\right]=\frac{ML^{2}}{T} \because M\rightarrow dimensionless
T=L2\therefore T=L^{2}\,\ell also dimensionless
Now p=mv=MLTM(is)p=mv=\frac{ML}{T} \,\because M\left(is\right) dimensionless
[p]=L1\therefore\left[p\right]=L^{-1}
[Energy]=ML2T2T=L2L2L2=L2\left[Energy\right]=\frac{ML^{2}}{T^{2}T}=\frac{L^{2}}{L^{2}L^{2}}=L^{-2}
[Power]=ML2T2T=L2L2L2L2=L4\left[Power\right]=\frac{ML^{2}}{T^{2}T}=\frac{L^{2}}{L^{2}L^{2}L^{2}}=L^{-4}
[Force]=MLT2=LL2L2=L3\left[Force\right]=\frac{ML}{T^{2}}=\frac{L}{L^{2}L^{2}}=L^{-3}