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Question: let us assume that the half-lives of a radioactive element for \(\alpha \) and \(\beta \) decay are ...

let us assume that the half-lives of a radioactive element for α\alpha and β\beta decay are 44 years and 1212 years respectively, then find the percentage of the element that remains after 1212 years?
A.6.25% B.12.5% C.25% D.50% \begin{aligned} & A.6.25\% \\\ & B.12.5\% \\\ & C.25\% \\\ & D.50\% \\\ \end{aligned}

Explanation

Solution

The number of half-lives completed due to the αdecay\alpha -decay and the βdecay\beta -decay is to be calculated first. Then the total number of half-lives that happened is to be found. The percentage of element remaining after 1212 years will be the reciprocal of the 2n{{2}^{n}} which is then multiplied by a hundred. This information will help you in solving this question.

Complete step-by-step solution
First of all, let us calculate the number of half-lives completed due to αdecay\alpha -decay. This can be found by taking the ratio of the total time after which the half-life is being calculated to the period of one half-life. That is,
number of half life=total time periodhalf life\text{number of half life=}\dfrac{\text{total time period}}{\text{half life}}
The half-life period of αdecay\alpha -decay is given as,
τalpha=4yrs{{\tau }_{alpha}}=4yrs
The total time period can be mentioned as,
t=12yrst=12yrs
Substituting the values in it will give,
nα=124=3{{n}_{\alpha }}=\dfrac{12}{4}=3
Similarly, we have to find the number of half-lives of the βdecay\beta -decay.
The half-life period of βdecay\beta -decay is given as,
τβ=12yrs{{\tau }_{\beta }}=12yrs
Substituting the values in it will give,
nβ=τβt{{n}_{\beta }}=\dfrac{{{\tau }_{\beta }}}{t}
Substituting the values in it will give,
nβ=1212=1{{n}_{\beta }}=\dfrac{12}{12}=1
Therefore the total number of the half-lives can be written as,
τ=τα+τβ\tau ={{\tau }_{\alpha }}+{{\tau }_{\beta }}
Substituting the values in it will give,
τ=3+1=4\tau =3+1=4
Hence the percentage of the element that remains after 12years12years will be calculated as,
P=12τ×100P=\dfrac{1}{{{2}^{\tau }}}\times 100
Substituting the values in it will give,
P=124×100=10016=6.25%P=\dfrac{1}{{{2}^{4}}}\times 100=\dfrac{100}{16}=6.25\%
Therefore the answer is calculated as per the question. It has been given as option A.

Note: Half-life is a common term in radioactivity, which is the interval of time needed for one-half of the atomic nuclei of a radioactive sample to decay. This will change spontaneously into other nuclear species by the emission of particles and energy. The element with the shortest half-life is francium.