Question
Question: let us assume that the half-lives of a radioactive element for \(\alpha \) and \(\beta \) decay are ...
let us assume that the half-lives of a radioactive element for α and β decay are 4 years and 12 years respectively, then find the percentage of the element that remains after 12 years?
A.6.25%B.12.5%C.25%D.50%
Solution
The number of half-lives completed due to the α−decay and the β−decay is to be calculated first. Then the total number of half-lives that happened is to be found. The percentage of element remaining after 12 years will be the reciprocal of the 2n which is then multiplied by a hundred. This information will help you in solving this question.
Complete step-by-step solution
First of all, let us calculate the number of half-lives completed due to α−decay. This can be found by taking the ratio of the total time after which the half-life is being calculated to the period of one half-life. That is,
number of half life=half lifetotal time period
The half-life period of α−decay is given as,
τalpha=4yrs
The total time period can be mentioned as,
t=12yrs
Substituting the values in it will give,
nα=412=3
Similarly, we have to find the number of half-lives of the β−decay.
The half-life period of β−decay is given as,
τβ=12yrs
Substituting the values in it will give,
nβ=tτβ
Substituting the values in it will give,
nβ=1212=1
Therefore the total number of the half-lives can be written as,
τ=τα+τβ
Substituting the values in it will give,
τ=3+1=4
Hence the percentage of the element that remains after 12years will be calculated as,
P=2τ1×100
Substituting the values in it will give,
P=241×100=16100=6.25%
Therefore the answer is calculated as per the question. It has been given as option A.
Note: Half-life is a common term in radioactivity, which is the interval of time needed for one-half of the atomic nuclei of a radioactive sample to decay. This will change spontaneously into other nuclear species by the emission of particles and energy. The element with the shortest half-life is francium.