Question
Question: Let U= {\(x:x\) is a letter in English alphabet}, A= {\(X:X\) is a vowel in English alphabet}, find ...
Let U= {x:x is a letter in English alphabet}, A= {X:X is a vowel in English alphabet}, find A’ and (A’)’.
Solution
To find a complement of a set, we subtract or remove its element from the universal set. The given sets are written in set builder notation; write it in roster notation to get clearer image in solving the question.
Complete step by step solution:
To solve this question, we will first elaborate the given data in the question. U is the universal set given in which all the alphabets of English are present and A is a set of all vowels in the English alphabets, in this manner we can say that A is a subset or a proper subset of the universal set U.
We can write this all in roster notation as follows
Now coming to the question, we have to find A’ and (A’)’, that is complement of A and A’ respectively.
Complement of a set is the set resulting from removal of the given set from the universal set.
According to this, A’ will be given as
And (A’)’ will be given as
(A’)’=U−A’=a, b, c, d, e, f, g, h, i, j, k, l, m, n, o, p, q, r, s, t, u, v, w, x, y, z− b, c, d, f, g, h, j, k, l, m, n, p, q, r, s, t, v, w, x, y, z (A’)’=a,e,i,o,uAdditional information: Complement of the universal set gives null set and also vice versa.
Note: U is denoted as the universal set. If we find a complement of a set then we will eventually get the set itself whose complement we have taken, it works just as negative of a negative equals positive. This question can also be solved with the help of Venn diagrams, try to solve it by yourself.