Question
Differential Equations Question on Differential Equations
Let θ∈(4π,2π). Consider the functions
u:R2−(0,0)→Randv:R2−(0,0)→R
given by
u(x,y)=x−x2+y2xandv(x,y)=y+x2+y2y.
The value of the determinant ∂x∂u ∂x∂v∂y∂u∂y∂v at the point (cosθ,sinθ) is equal to
A
4sinθ.
B
4cosθ.
C
(4 \sin^2 \theta.\
D
4cos2θ.
Answer
4cos2θ.
Explanation
Solution
The correct option is (D): 4cos2θ.