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Question

Mathematics Question on Tangents and Normals

Let the tangents at the points A(4, –11) and B(8, –5) on the circle x2+y23x+10y15=0x^2+y^2-3x+10y-15=0, intersect at the point C. Then the radius of the circle, whose centre is C and the line joining A and B is its tangent, is equal to

A

√13

B

3√3/4

C

2√13/3

D

2√13

Answer

2√13/3

Explanation

Solution

The correct answer is 2√13/3