Question
Mathematics Question on Tangents and Normals
Let the tangents at the points A(4, –11) and B(8, –5) on the circle x2+y2−3x+10y−15=0, intersect at the point C. Then the radius of the circle, whose centre is C and the line joining A and B is its tangent, is equal to
A
√13
B
3√3/4
C
2√13/3
D
2√13
Answer
2√13/3
Explanation
Solution
The correct answer is 2√13/3