Question

Let the tangent and normal at the point $(3\sqrt{3},1)$ on the ellipse $\frac{ x^2}{36}+\frac{y^2}{4} =1$ meet the y-axis at the points A and B respectively. Let the circle C be drawn taking AB as a diameter and the line x = $2\sqrt{5}$ intersect C at the points P and Q. If the tangents at the points P and Q on the circle intersect at the point (α,β) , then α2 - β2 is equal to

• A. 60
• B. 61
• C. $\frac{304}{5}$
• D. $\frac{314}{5}$

Answer 1

Answer: (C)

$\frac{304}{5}$

Answer 2

The correct option is(C): $\frac{304}{5}$