Question

Let the solubilities of AgCl in pure water, 0.01 M CaCl₂, 0.01 M NaCl& 0.05 M AgNO3 be s1, s2, s3& s4 respectively what is the correct order of these quantities . Neglect any complexation.

• A. $S_{1} > S_{2} > S_{3} > S_{4}$
• B. $S_{1} > S_{2} = S_{3} > S_{4}$
• C. $S_{1} > S_{3} > S_{2} > S_{4}$
• D. $S_{4} > S_{2} > S_{3} > S_{1}$

Answer 1

Answer: (C)

$S_{1} > S_{3} > S_{2} > S_{4}$

Answer 2

Let Ksp of AgCI = x

(1) solubility of AgCl in pure water = s1 = $\sqrt{x}$

(2) solubility of AgCl in 0.01 M CaCl2 = s2 = $\frac{x}{0.02}$

(3) solubility of AgCl in 0.01 M NaCl = s3 = $\frac{x}{0.01}$

(4) solubility of AgCl in 0.05 M AgNO3 = s4 =$\frac{x}{0.05}$

So, s1 > s3 > s2 > s4