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Question

Mathematics Question on Set Theory

Let the set C=(x,y)x22y=2023,x,yNC = \\{(x, y) \mid x^2 - 2^y = 2023, x, y \in \mathbb{N}\\}.Then(x,y)C(x+y)\sum_{(x, y) \in C} (x + y)is equal to ______.

Answer

Given the equation: x22y=2023x^2 - 2^y = 2023

Step 1. By trial, we find that x=45x = 45 and y=1y = 1 satisfy the equation, as:

45221=20252=202345^2 - 2^1 = 2025 - 2 = 2023

Step 2. Thus, the only solution in CC is (x,y)=(45,1)(x, y) = (45, 1).

Step 3. Calculate (x,y)C(x+y)\sum_{(x, y) \in C} (x + y):

(x,y)C(x+y)=45+1=46\sum_{(x, y) \in C} (x + y) = 45 + 1 = 46

The Correct Answer is: 46