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Question

Question: Let the positive numbers \(a,b,c,d\) be in A.P. then \(abc, abd, acd, bcd\) are (a) not in A.P./G....

Let the positive numbers a,b,c,da,b,c,d be in A.P. then abc,abd,acd,bcdabc, abd, acd, bcd are
(a) not in A.P./G.P./H.P.
(b) in A.P.
(C) in G.P.
(d) in H.P.

Explanation

Solution

Hint: Try to obtain the required terms from given terms using properties of sequences.

Since ,it is given that a,b,c,da,b,c,d are in A.P., then d,c,b,ad,c,b,a are also in A.P.
A series of terms is known as a H.P. series when the reciprocals of elements are
in arithmetic progression or A.P.
So,
1d,1c,1b,1a\Rightarrow \dfrac{1}{d},\dfrac{1}{c},\dfrac{1}{b},\dfrac{1}{a} are in H.P.
Thus, after multiplying the above terms with abcdabcd,
We get,
abcdd,abcdc,abcdb,abcda\Rightarrow \dfrac{{abcd}}{d},\dfrac{{abcd}}{c},\dfrac{{abcd}}{b},\frac{{abcd}}{a} are in H.P.
abc,abd,acd,bcd\Rightarrow abc, abd, acd, bcd are in H.P.
Hence, the required answer is (d) in H.P.

Note: To solve these types of questions, perform the specific manipulations and obtain the required solution.