Question
Mathematics Question on linear inequalities in one variable
Let the position vectors of the points P, Q, R and S be
a=i^+2j^−5k^, b=3i^+6j^+3k^, c=517i^+516j^+7k^ and d=2i^+j^+k^
respectively. Then which of the following statements is true?
The points P,Q,R and S are NOT coplanar
3b+2d is the position vector of a point that divides PR internally in the ratio 5:4
3b+2d is the position vector of a point that divides PR externally in the ratio 5:4
The square of the magnitude of the vector b×d is 95
3b+2d is the position vector of a point that divides PR internally in the ratio 5:4
Solution
Given :
The position vector of point P is given by: P=i^+2j^−5k^
The position vector of point R is given by: R=517i^+516j^+7k^
Now, let's find the position vector of the point that divides PR internally in the ratio 5:4. This can be done using the section formula:
4 M =5+45 R +4 P
M=95(517i^+516j^+7k^)+4(i^+2j^−5k^)
M=917i^+16j^+35k^+4i^+8j^−20k^
M=921i^+24j^+15k^
M=37i^+8j^+5k^
This is the same as 3 b +2 d , which confirms that the option (B) is indeed correct. It represents a point that divides PR internally in the ratio 5:4.
So, the correct option is (B): 3b+2d is the position vector of a point that divides PR internally in the ratio 5:4