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Question

Mathematics Question on linear inequalities in one variable

Let the position vectors of the points P, Q, R and S be
a=i^+2j^5k^\vec{a}=\hat{i}+2\hat{j}-5\hat{k}, b=3i^+6j^+3k^\vec{b}=3\hat{i}+6\hat{j}+3\hat{k}, c=175i^+165j^+7k^\vec{c}=\frac{17}{5}\hat{i}+\frac{16}{5}\hat{j}+7\hat{k} and d=2i^+j^+k^\vec{d}=2\hat{i}+\hat{j}+\hat{k}
respectively. Then which of the following statements is true?

A

The points P,Q,R and S are NOT coplanar

B

b+2d3\frac{\vec{b}+2\vec{d}}{3} is the position vector of a point that divides PR internally in the ratio 5:4

C

b+2d3\frac{\vec{b}+2\vec{d}}{3} is the position vector of a point that divides PR externally in the ratio 5:4

D

The square of the magnitude of the vector b×d\vec{b}\times \vec{d} is 95

Answer

b+2d3\frac{\vec{b}+2\vec{d}}{3} is the position vector of a point that divides PR internally in the ratio 5:4

Explanation

Solution

Given :
The position vector of point P is given by: P=i^+2j^5k^\vec{P} = \hat{i} + 2\hat{j} - 5\hat{k}
The position vector of point R is given by: R=175i^+165j^+7k^\vec{R} = \frac{17}{5}\hat{i} + \frac{16}{5}\hat{j} + 7\hat{k}
Now, let's find the position vector of the point that divides PR internally in the ratio 5:4. This can be done using the section formula:
4 M =5+45 R +4 P
M=5(175i^+165j^+7k^)+4(i^+2j^5k^)9\vec{M} = \frac{5\left(\frac{17}{5}\hat{i} + \frac{16}{5}\hat{j} + 7\hat{k} \right) + 4\left(\hat{i} + 2\hat{j} - 5\hat{k} \right)}{9}
M=17i^+16j^+35k^+4i^+8j^20k^9\vec{M} = \frac{17\hat{i} + 16\hat{j} + 35\hat{k} + 4\hat{i} + 8\hat{j} - 20\hat{k}}{9}
M=21i^+24j^+15k^9\vec{M} = \frac{21\hat{i} + 24\hat{j} + 15\hat{k}}{9}
M=7i^+8j^+5k^3\vec{M} = \frac{7\hat{i} + 8\hat{j} + 5\hat{k}}{3}
This is the same as 3 b +2 d ​, which confirms that the option (B) is indeed correct. It represents a point that divides PR internally in the ratio 5:4.
So, the correct option is (B): b+2d3\frac{\vec{b}+2\vec{d}}{3} is the position vector of a point that divides PR internally in the ratio 5:4