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Question

Mathematics Question on Straight lines

Let the orthocenter an centroid of a triangle be A(3,5)A(-3, 5) and B(3,3)B(3, 3) respectively. If CC is the circumcentre of this triangle, then the radius of the circle having line segment ACAC as diameter, is:

A

10\sqrt{10}

B

2102 \sqrt{10}

C

3523 \sqrt{\frac{5}{2}}

D

352 \frac{3\sqrt{5}}{2}

Answer

3523 \sqrt{\frac{5}{2}}

Explanation

Solution

A(3,5)A(-3,5)
B(3,3)B(3,3)

So, AB=210A B=2 \sqrt{10}
Now, as, AC=32ABA C=\frac{3}{2} A B
So, radius =34AB=3210=352=\frac{3}{4} A B=\frac{3}{2} \sqrt{10}=3 \sqrt{\frac{5}{2}}