Question

Let the line passing through the points P (2, –1, 2) and Q (5, 3, 4) meet the plane x – y + z = 4 at the point R. Then the distance of the point R from the plane x + 2y + 3z + 2 = 0 measured parallel to the line $\frac{x-7}{2}=\frac{y+3}{2}=\frac{z-2}{1}$ is equal to

• A. $\sqrt{189}$
• B. $\sqrt{31}$
• C. $\sqrt{61}$
• D. 3

Answer 1

Answer: (D)

3

Answer 2

The Correct Option is(D):3