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Question

Mathematics Question on Functions

Let the function f:RRf:\R→\R be defined by
f(x)=sinxeπx(x)2023+2024x+2025(x2x+3)+2eπx(x2023+2024x+2025)(x2x+3)f(x)=\frac{\sin x}{e^{\pi x}}\frac{(x)^{2023}+2024x+2025}{(x^2-x+3)}+\frac{2}{e^{\pi x}}\frac{(x^{2023}+2024x+2025)}{(x^2-x+3)}
Then the number of solutions of f (x) = 0 in R\R is __.

Answer

The correct answer is: 1.