Question

Let the ellipse, $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1, a > b,$ pass through the point (2, 3) and have eccentricity equal to $\frac{1}{2}$. Then equation of the normal to this ellipse at $(2,3)$ is :

• A. $2y-x=4$
• B. $2x-y=1$
• C. $3x-2y=0$
• D. $3x-y=3$

Answer 1

Answer: (B)

$2x-y=1$

Answer 2

Answer (b) $2x-y=1$