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Question

Mathematics Question on Hyperbola

Let the eccentricity of the hyperbola
H:x2a2y2b2=1H : \frac{x²}{a²} - \frac{y²}{b²} = 1
be √(5/2) and length of its latus rectum be 6√2, If y = 2 x + c is a tangent to the hyperbola H. then the value of c 2 is equal to

A

18

B

20

C

24

D

32

Answer

20

Explanation

Solution

The correct answer is (B) : 20
1+b2a2=52b2a2=321 + \frac{b²}{a²} = \frac{5}{2} ⇒ \frac{b²}{a²} = \frac{3}{2}
2b2a=62=2.32.a=62\frac{2b²}{a} = 6\sqrt2 = 2 . \frac{3}{2} . a = 6\sqrt2
a=22,b2=12⇒ a = 2\sqrt2 , b² = 12
c2=a2m2b2=8.412=20c² = a²m² - b² = 8.4 - 12 = 20