Question

Let tan⁡α=aa+1 and tan⁡β=12a+1 then α+β is

• A. (A) π/4
• B. (B) π/3
• C. (C) π/2
• D. (D) π

Answer 1

Answer: (A)

(A) π/4

Answer 2

Explanation:
tan⁡α=aa+1,tan⁡β=12a+1tan⁡(α+β)=aa+1+12a+11−a(a+1)(2a+1)=a(2a+1)+a+1(a+1)(2a+1)(a+1)(2a+1)−a(a+1)(2a+1)=2a2+2a+12a2+2a+1=1α+β=π4