Question

Let
$𝑆_𝑛 =∑_{k=1}^n\frac{1+k2^k}{4^{k-1}},n=1,2,...$
Then, lim𝑛→∞ 𝑆𝑛 equals (round off to two decimal places)

Answer 1

The correct answer is: 9.32 to 9.34 (approx)