Question

Let S=\left\\{(x,y)\in\R\times\R:x\ge0,y\ge0,y^2\le12-2x\ \text{and}\ 3y+\sqrt8\ x\le5\sqrt8\right\\}. If the area of the region S is $\alpha\sqrt2$, then α is equal to

• A. $\frac{17}{2}$
• B. $\frac{17}{3}$
• C. $\frac{17}{4}$
• D. $\frac{17}{5}$

Answer 1

Answer: (B)

$\frac{17}{3}$

Answer 2

The correct option is (B):$\frac{17}{3}$