Question
Mathematics Question on Quadratic Equations
Let S be the set of positive integral values of a for which x2−8x+32ax2+2(a+1)x+9a+4<0,∀x∈R. Then, the number of elements in S is:
A
1
B
0
C
∞
D
3
Answer
0
Explanation
Solution
Consider the inequality:
ax2+2(a+1)x+9a+4<0∀x∈R
For the quadratic to be negative for all values of x, the coefficient of x2 must be negative:
a<0
Since we are looking for positive integral values of a, no such values exist.