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Question

Mathematics Question on Arithmetic Progression

Let S be the set of all right angled triangles with integer sides forming consecutive terms of an arithmetic progression. The number of triangles in S with perimeter less than 30 is

A

0

B

1

C

2

D

3

Answer

2

Explanation

Solution

Let the side of right angled triangles are
x,x+1,x+2x, x + 1, x + 2
(x+2)2=(x+1)2+(x)2\therefore (x+2)^2 = (x+1 )^2 +(x)^2
x2+4x+4=x2+2x+1+x2⇒ x^2 + 4x + 4 = x^2 +2x +1 + x^2
x22x3=0⇒ x ^2 − 2x− 3 = 0
(x3)(x+1)=0⇒ (x-3 )(x+ 1 )= 0
x=3,x1⇒ x = 3, x ≠ − 1
Perimeter of triangle =3x+3= 3 x + 3
3x+3<303x + 3 < 30
x+1<10x + 1 < 10
x<9x < 9
The possible triangle whose sides are
(3,4,5),(6,8,10)(3, 4, 5), (6, 8, 10)
Two triangles are possible
Therefore, the Correct Option is (C) 2