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Question

Mathematics Question on Probability

Let SS be a set containing n elements and we select two subsets AA and DD of S at random, then the probability that AB=SA \cup B = S and AB=ϕA \cap B = \phi is:

A

2n2^n

B

n2n^2

C

1n\frac{1}{n}

D

12n\frac{1}{2^n}

Answer

12n\frac{1}{2^n}

Explanation

Solution

Given that SS contains nn elements and two sets AA and BB are selected. Two sets AA and BB can be selected in 2n2^{ n } ways. The number of ways of selecting two sets such that their union is SS and intersection is nullset is 11 . Therefore the probability is 12n\frac{1}{2^{n}}.