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Question

Mathematics Question on Sets

Let S=1,2,3,,10S = \\{ 1, 2, 3, \ldots, 10 \\}. Suppose MM is the set of all the subsets of SS, then the relation R=(A,B):ABϕ;A,BMR = \\{ (A, B): A \cap B \neq \phi; A, B \in M \\} is:

A

symmetric and reflexive only

B

reflexive only

C

symmetric and transitive only

D

symmetric only

Answer

symmetric only

Explanation

Solution

Let’s analyze the properties of the relation RR.

Step 1. Reflexivity: For reflexivity to hold, each subset AA in MM should satisfy AAA \cap A \neq \emptyset. Since AA=AA \cap A = A, RR would be reflexive if AA \neq \emptyset for every AMA \in M. However, the empty set M\emptyset \in M does not satisfy \emptyset \cap \emptyset \neq \emptyset, so RR is not reflexive.

Step 2. Symmetry: If (A,B)R(A, B) \in R, then ABA \cap B \neq \emptyset. This implies BAB \cap A \neq \emptyset, so (B,A)R(B, A) \in R. Therefore, RR is symmetric.

Step 3. Transitivity: Suppose (A,B)R(A, B) \in R and (B,C)R(B, C) \in R, meaning ABA \cap B \neq \emptyset and BCB \cap C \neq \emptyset. However, ACA \cap C may still be empty, so RR is not transitive.

Thus, the relation RR is symmetric only.