Question
Mathematics Question on Functions
Let R=\left\\{ \left(3,3\right) \left(5,5\right), \left(9,9\right), \left(12,12\right), \left(5,12\right), \left(3,9\right), \left(3,12\right), \left(3,5\right)\right\\} be a relation on the set A=\left\\{3,5,9,12\right\\}. Then, R is:
reflexive, symmetric but not transitive
symmetric, transitive but not reflexive
an equivalence relation
reflexive, transitive but not symmetric
reflexive, transitive but not symmetric
Solution
Let R=\left\\{ \left(3,3\right) \left(5,5\right), \left(9,9\right), \left(12,12\right), \left(5,12\right), \left(3,9\right), \left(3,12\right), \left(3,5\right)\right\\} be a relation on the set A=\left\\{3,5,9,12\right\\}
Clearly, every element of A is related to itself. Therefore, it is a reflexive.
Now, R is not symmetry because 3 is related to 5 but 5 is not related to 3.
Also R is transitive relation because it satisfies the property that if a R b and b R c then aRc.