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Question

Mathematics Question on Functions

Let R=\left\\{ \left(3,3\right) \left(5,5\right), \left(9,9\right), \left(12,12\right), \left(5,12\right), \left(3,9\right), \left(3,12\right), \left(3,5\right)\right\\} be a relation on the set A=\left\\{3,5,9,12\right\\}. Then, RR is:

A

reflexive, symmetric but not transitive

B

symmetric, transitive but not reflexive

C

an equivalence relation

D

reflexive, transitive but not symmetric

Answer

reflexive, transitive but not symmetric

Explanation

Solution

Let R=\left\\{ \left(3,3\right) \left(5,5\right), \left(9,9\right), \left(12,12\right), \left(5,12\right), \left(3,9\right), \left(3,12\right), \left(3,5\right)\right\\} be a relation on the set A=\left\\{3,5,9,12\right\\}
Clearly, every element of A is related to itself. Therefore, it is a reflexive.
Now, RR is not symmetry because 3 is related to 5 but 5 is not related to 3.
Also RR is transitive relation because it satisfies the property that if a R b and b R c then aRc.a\,R\,c.