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Question: Let R be a relation over the set N × N and it is defined by \(( a , b ) R ( c , d ) \Rightarrow a + ...

Let R be a relation over the set N × N and it is defined by (a,b)R(c,d)a+d=b+c( a , b ) R ( c , d ) \Rightarrow a + d = b + c Then R is

A

Reflexive only

B

Symmetric only

C

Transitive only

D

An equivalence relation

Answer

An equivalence relation

Explanation

Solution

We have (a,b)R(a,b)( a , b ) R ( a , b )for all (a,b)N×N( a , b ) \in N \times N

Since a+b=b+aa + b = b + a. Hence, R is reflexive.

R is symmetric for we have(a,b)R(c,d)( a , b ) R ( c , d )a+d=b+ca + d = b + c

c+b=d+a(c,d)R(e,f)c + b = d + a \Rightarrow ( c , d ) R ( e , f )

Then by definition of R, we have

a+d=b+ca + d = b + cand c+f=d+ec + f = d + e,

whence by addition, we get

a+d+c+f=b+c+d+ea + d + c + f = b + c + d + e or a+f=b+ea + f = b + e

Hence,(a,b)R(e,f)( a , b ) R ( e , f )

Thus, (a, b)R(c,d)R ( c , d )and (c,d)R(e,f)(a,b)R(e,f)( c , d ) R ( e , f ) \Rightarrow ( a , b ) R ( e , f ).