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Question: Let \[R\] be a relation from a set \[A\] to a set \[B\], then: A) \[R = A \cup B\] B) \[R = A \c...

Let RR be a relation from a set AA to a set BB, then:
A) R=ABR = A \cup B
B) R=ABR = A \cap B
C) RA×BR \subseteq A \times B
D) RB×AR \subseteq B \times A

Explanation

Solution

Here we will be using the property of sets and Venn diagrams which states that if any relation is from a set AA to set BB then it is a subset of A×BA \times B where the subset symbol denotes as \subseteq.

Complete step-by-step solution:
Step 1: Let set A = \left\\{ {1,2} \right\\} and set B = \left\\{ a \right\\}, A×BA \times B will be equals to as below:
\Rightarrow A \times B = \left\\{ {\left( {1,a} \right),\left( {2,a} \right)} \right\\}
But as given in the question that
RR is a relation from a set AA to a set BB, so we can write the relation as below:
R=A×B\Rightarrow R = A \times B
Which also means that relation RR is a subset of A×BA \times B.

\because The relation between RR and A×BA \times B is RA×BR \subseteq A \times B.

Note: Students needs to remember some important points of sets and relations as mentioned below:
If a set A = \left\\{ {1,2,3,4} \right\\} and set B = \left\\{ {0,1,2,3,4} \right\\}, then we can say that set AA is a subset of the set
BB because all the elements AA belong to BB, so we can write as ABA \subseteq B. But the set BB is not a subset of AA because 0A0 \notin A. So, we can write as B⊄AB \not\subset A
Any set SS is a subset of itself because every element SS is an element of SS.
An empty set is always a subset of every set SS because every element of an empty set is an element of SS. An empty set is denoted by the symbol ϕ\phi and it means that there are no elements in it.
Suppose SS is a finite set( which means that we can list all of its elements ), then the symbol S\left| S \right| denotes the number of elements in that set.