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Question

Mathematics Question on Relations and functions

Let R = {a, b, c, d, e} and S = {1, 2, 3, 4}. Then number of onto functions f(x) : R → S such that f(a) ≠1 is?

A

240

B

180

C

204

D

216

Answer

180

Explanation

Solution

The correct answer is (B) : 180
Total no. of onto functions
=5!3!2!×4!=\frac{5!}{3!2!}\times4!
So , when f(a) = 1
4!2!2!×3!+4!\frac{4!}{2!2!}\times3!+4!
\therefore Required functions :
= 240 -36 -24
=180