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Question

Mathematics Question on Integration by Partial Fractions

Let R 1 and R 2 be two relations defined on ℝ by a R 1 bab ≥ 0 and a R 2 ba ≥ _b. _Then,

A

R 1 is an equivalence relation but not R 2

B

R 2 is an equivalence relation but not R 1

C

Both R 1 and R 2 are equivalence relations

D

Neither R 1 nor R 2 is an equivalence relation

Answer

Neither R 1 nor R 2 is an equivalence relation

Explanation

Solution

_The correct answer is (D):
aR_1 bab ≥ 0
So, definitely (a , a) ∈ R 1 as a 2 ≥ 0
If (a , b) ∈ R 1 ⇒ (b , a) ∈ R 1
But if (a , b) ∈ R 1, (b , c) ∈ R 1
⇒ Then (a , c) may or may not belong to R 1
{Consider a = -5, b = 0, c = 5 so (a , b) and (b , c) ∈ R 1 but ac < 0}
So, R 1 is not equivalence relation
a R 2 ba ≥ _b
_(a , a) ∈ R 2 ⇒ so reflexive relation
If (a , b) ∈ R 2 then (b , a) may or may not belong to R 2
⇒ So not symmetric
Hence it is not equivalence relation